Calculate the calorific value of methane, when methane undergoes combustion?
(ΔH f(CH4) = 55.4 KJmol-1)
Answers
Answer:
At STP, 1 mole of any gas occupies a volume of 22.4 L.
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.4
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4 will be obtained from 3 moles of CO
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4 will be obtained from 3 moles of CO 2
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4 will be obtained from 3 moles of CO 2
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4 will be obtained from 3 moles of CO 2 .
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4 will be obtained from 3 moles of CO 2 .The molar mass of methane is 16 g/mol.
At STP, 1 mole of any gas occupies a volume of 22.4 L.The volume of 67.2 L corresponds to 22.467.2 =3 moles.1 mole of CO 2 is obtained from 1 mole of CH 4 .3 moles of CH 4 will be obtained from 3 moles of CO 2 .The molar mass of methane is 16 g/mol.The mass of 3 moles of methane will be 3×16=48g
Explanation:
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