Question

Calculate the capacitance of a parallel plate capacitor with dielectric medium 6 if the separation between the plates 8.85mm and plate area6×10^-4 m^2

Answer 1

Answer:

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Answer 2

Answer:

$capacitance\ =\ 3.6\times 10^{-13}\ F$

Explanation:

Given,

dielectric constant of the dielectric medium,k = 6

separation between plates, d = 8.85 mm

                                                $=\ 8.85\times 10^{-3}\ m$

$area\ of\ the\ plate,\ a=\ 6\times 10^{-4}\ m^2$

permittivity of space between the plates,

       $\epsilon\ =\ 8.854\times 10^{-12} F/m$

Capacitance of the capacitor is given by,

  $C\ =\ \dfrac{k.\epsilon.a}{d}$

       $=\dfrac{6\times 8.85\times 10^{-12}\times 6\times 10^{-4}}{8.85\times 10^{-3}}$

        $= 3.6\times 10^{-13} F$

Hence, the capacitance of the capacitor is $3.6\times 10^{-13}\ F.$