Question

Calculate the cell emf and Gibbs free energy for the cell reaction at 25°C for the cell
Zn(s) | Zn2+(0.0004 M) || Cd 2+ (0.2 M) | Cd
Zn 2+ | Zn =-0.763 V, Cd2+ | Cd =-0.430
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Answer 1

5×5=25

Explanation:

1. The cell emf and Gibbs free energy for the cell reaction is=25°celsius for the cell Zn(s)zn2×1+2×2
2. Hence the cell and gibbs is equal to 25°c

Answer 2

Answer:

hope it will help you

Explanation:

1. the cell end and gibbs

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