Calculate the cell potential of a hydrogen electrode in contact with a solution whose ph is 10.
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we have equation for standard reduction potential as
2H+ +2e- ------H2
we have
E=E0 -.059/nlog[H]/[H+]^2
E0=0
n=2
[H]=1
E=-.06/2*log[H+]^-2
E=-log[H+]*(-.06)
=pH*.06=10*.6=-.6V
Thus the potential of hydrogen electrode whose ph is 10 is -.6V
dheeraj9999:
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