Question

Calculate the Centroid of the triangle whose vertices are x(2,2),y( 3,3)&z(4,5).​

Answer 1

$\large{\red{\bold{\underline{Given:}}}}$

$\sf \: Coordinates \: of \: the \: vertices \: are: \: x(2,2), \: y(3,3) \: and \: z(4,5)$

$\large{\green{\bold{\underline{To \: Find:}}}}$

$\sf \: Centroid \: of \: the \: triangle$

$\large{\blue{\bold{\underline{Formula \: Used:}}}} \\ \\ \sf \:Coordinates \: of \:Centroid = \: (\frac{x_{1} + x_{2} + x_{3}}{3} ),( \frac{y_{1} + y_{2} + y_{3}}{3})$

$\large{\red{\bold{\underline{Solution:}}}} \\ \\ \: \sf \: On \: considering \: the \: respective \: coordinates \: as :$

$\sf \: x(2,2) \: \rightarrow \: (x_{1}, y_{1}) \\ \\\sf \: y(3,3) \: \rightarrow \: (x_{2}, y_{2}) \\ \\ \sf \: z(4,5) \: \rightarrow \: (x_{3}, y_{3})$

$\large{\pink{\bold{\underline{Now:}}}} \\ \\ \rightarrow \: \sf \: Centroid = ( \frac{2 + 3 + 4}{3}) ,( \frac{2 + 3 + 5}{3} ) \\ \\ \rightarrow \sf \: Centroid = ( \frac{\cancel9}{\cancel3}) , (\frac{10 }{3} ) \\ \\ \rightarrow \sf \: Centroid = ( \frac{3}{1} ),( \frac{10}{3} ) \\ \\ \rightarrow \sf \: Centroid = (3,3.3)$

$\large{\orange{\bold{\underline{Therefore:}}}} \\ \\ \sf \: The \: coordinates \: of \: Centroid \: of \: the \: triangle \\ \sf \: is \: (3,3.3).$

Answer 2

Answer:

upload the figure

Explanation:

without figure it cannot be solved