Question

calculate the change in angular momentum of an electron in hydrogen atom when it jumps from ground state to 2nd energy level

Answer 1

$\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}$

To find the Change in Angular Momentum of the electron

Angular Momentum is given by:

$\huge{ \boxed{ \boxed{ \sf{mvr = n \frac{h}{2 \pi} }}}}$

Here,"n" can be any natural number

The electron jumps from first level to second level

• When n = 1,

$\displaystyle{\sf{{P}_{i} = \frac{h}{2 \pi}}}$

• When n = 2,

$\displaystyle{\sf{P}_{f} = \frac{2h}{2 \pi}}}$

Change in Momentum

$\sf{\Delta{P} = {P}_{f} - {P}_{i} } \\ \\ \implies \ \sf{\Delta{P} = \frac{2h}{2 \pi} - \frac{h}{2 \pi}} \\ \\ \implies \ \sf{\Delta{P} = \frac{h}{2 \pi}}$

$\implies \: \sf{\Delta{p} \: = \: \frac{6.626 \times 10 {}^{ - 34} }{3.14 \times 2} } \\ \\ \huge{ \implies \: \sf{ \Delta{p}} = 1.055 \times 10 {}^{ - 34} Kg.m/s }$

Answer 2

Answer:

Refer the attached picture.