Question

calculate the change in entropy of when 10grams of ice at 0 degree centegrade converted into steam at 100degree centegrade latent heat of steam is 80cal/ gram​

Answer 1

Explanation:

The change in entropy would be given as ΔS=ΔS1+ΔS2 ΔS1 is to melt the ice and ΔS2 is to rise the temperature. Thus we get ΔS=TmL+m∫T1T2TdT

ΔS=2731×80+1×ln273313=0.28+0.13=0.41 cal/oC