Calculate the change in internal energy of 3 mol of helium gas when it's temprature is increased by 2 K .
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Heya......!!!!
Helium is a monoatomic gas . Internal energy of n moles of the gas is
=> U = 3/2 × NRT
=> ∆ U = 3/2 nr ( ∆ T )
Substituting the values ,,
∆ U = 3/2 × 3×8.31×2
∆ U = 74.8 J .
Hope it helps u
Helium is a monoatomic gas . Internal energy of n moles of the gas is
=> U = 3/2 × NRT
=> ∆ U = 3/2 nr ( ∆ T )
Substituting the values ,,
∆ U = 3/2 × 3×8.31×2
∆ U = 74.8 J .
Hope it helps u
Answered by
0
Internal energy =
U = 3/2 × 3×8.31×2
∆ U = 74.8 J .
U = 3/2 × 3×8.31×2
∆ U = 74.8 J .
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