Question

Calculate the change in kinetic energy for a bicycle of mass 20 kg to
increase its speed from 2ms-1
to 3ms-1

Answer 1

Given :-

⇒ m = 20kg

⇒ v (initial) = 2 m/s

⇒v (final) = 3 m/s

Solution :-

$\bf{\rightarrow\:\:K.E = \frac{1}{2} \:m\:(v_{final}-v_{initial})^2$

$\bf{\rightarrow\:\:K.E = \frac{1}{2} \:20\:(3-2)^2$

$\bf{\rightarrow\:\:K.E = \frac{20}{2}\:(1)^2$

$\bf{\rightarrow\:\:K.E = 10\:Joules$

Final Answer :-

The change in kinetic energy for a bicycle of mass 20 kg to increase its speed from 2 m/s to 3 m/s is 10 J.

_______________________________________________

Thank you please mark as brainliest!

$\bf{\rightarrow\:\:ANAGH$ :)