Calculate the change in length of the upper leg bone (the femur) when a 70.0 kg man
supports 62.0 kg of his mass on it, assuming the bone to be equivalent to a uniform rod
that is 40.0 cm long and 2.00 cm in radius.
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Calculate the change in length of the upper leg bone (the femur) when a 70.0 kg man supports 62.0 kg of his mass on it, assuming the bone to be equivalent to a uniform rod that is 40.0 cm long and 2.00 cm in radius. F=mg=(62.0 kg)(9.80 m/s2)=607.6 N, and the cross-sectional area is πr2 = 1.257 × 10-3 m2
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