Question

calculate the change in momentum in percentage if its mass become 3 by 2 and velocity become 1 by 3

Answer 1

Let the initial velocity be 'v'
Let the initial Mass be 'm'

The final velocity is. v/3
The final mass is. 3m/2


Initial momentum= mv

Final momentum = (v/3) * (3m/2) = mv/2.


change in momentum = initial - final momentum.
= mv-(mv/2)
= mv/2= 0.5 mv


Percentage change = change in momentum/ initial momentum *100

= 0.5mv/mv*100 = 50%. but it decreases so it's -50%.



Hope this helps.

Answer 2

Answer: - 50%.

Explanation:

Let, initial mass = m,

initial velocity = v.

So, p = mv.

Now, mass becomes = 3/2 m

And, velocity = 1/3 v

Thus, p′ = 3/2 m × 1/3 v

=> p′ = 1/2 mv

So, ∆p (in %) = (p′ - p)/p 100%

=> ∆p (in %) = (1/2 mv - mv)/mv 100%

=> ∆p (in %) = (1/2 - 1) 100%

=> ∆p (in %) = = - 50%.