Question

calculate the change in momentum of a car of mass 2000 kg when its speed increases from 20 km/h to 60 km/h uniformly
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Answer 1

Answer:

your answer okkkkkkkkkkkk

Explanation:

HENCE, the change in momentum is 2 into 104/ kmg/s

Answer 2

Answer:

The change in momentum of a car of mass 2000 kg when its speed increases from 20 km/h to 60 km/h uniformly will be $= 22222$.

Explanation:

The momentum of an object can be represented as,

$Momentum (P)= mass(m)\times velocity(v)$   ...(1)

Using the above equation,

Initial momentum  $(p_1)\ = mu$      ...(2)

Final momentum    $(p_2 )\ = mv$     ...(3)

The change in momentum ($\Delta P$) will be,

 $\Delta K.E = p_1 - p_2=\ mu - mv$

            $= m(v - u)$                        ...(4)

Given,

Mass of the car (m) = $2000$ kg

Initial speed of the car  (u)      =  $20$ km/h

Final speed of the car  (v)       =  $60$  km/h

Convert km/h into m/s by multiplying the velocity with $\frac{5}{18}$

$u = 20 \times \frac{5}{18}$ $= \frac{50}{9} \ m/s$

$v = 60 \times \frac{5}{18}$$= \frac{150}{9} \ m/s$

Substitutes the values into equation(2).

$\Delta P = \ 2000\times( \frac{150}{9} - \frac{50}{9} )$

        $= 22222$ kgm/s

So, the change in momentum  $= 22222$ kgm/s