Question

calculate the change in pressure in the following cases.
1) when Area on which a force acting is halved.
2) when force acting on area is doubled, while are is halved
3) when force acting on area is halved, while area is doubled.


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Answer 1

Answer:

pressure becomes double if area becomes half thats the answer i explained it hope you like

Answer 2

1)as we know that pressure(p)=force(f)/area(a)

now area is halved =a/2, then let the new pressure be p'

so p/p'= (f/a)/(2f/a)=(f/a)*(a/2f)=1/2

     2p=p'

so this means that when area is halved then pressure is doubled.

2) when force is doubled=2f and area is halved=a/2

so the new pressure is p'= 2*2f/a=4f/a

so now p/p'= (f/a)*(a/4f)=1/4

so 4p=p'

so the new pressure is increased by 4 times now

3)  when the force is half =f/2 and area is doubled=2a

       so the new pressure p' is= (f/2)*(1/2a)=f/4a

so now p/p'= (f/a)*(4a/f)=4

p/4=p'

so the new pressure is reduced by 4 times