Calculate the change in temperature dT of boiling water when pressure is increases by
27.12 mm of mercury.(Given: boiling point of water = 1000C, latent heat of steam = 537
cal/g , g = 980 cm/s2, r =13.6gm/cm3 specific volume of steam = 1674 cm3)
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Answer:
dP = 10 -1 =9 atm = 9 x 106dyne / cm2
T = Boiling point of water = 1000c = 373 K
V2= 1677 cc /gm
V1 = 1 cc /gm
V2 - V2 = 1676 cc/gm
L = 540 Cal/gm
= 540 x 4.2 x107 erg/gm
dt = 248.07 K
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