Question

Calculate the change in the length of a simple pendulum of length 1m , when its period of oscillation from 2s to 1.5s??​

Answer 1

Answer:

L =( g*T^2) / (4 * pi^2). Substituting the value for g = 9.8 m s^-2, and T = 1.5 s, I get for the pendulum length L = 0.56 m.

Explanation:

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Answer 2

$\large{\bf{\red{\underline{\underline{Question:}}}}}$

Calculate the change in the length of a simple pendulum of length 1m , when its period of oscillation from 2s to 1.5s??

$\large{\bf{\green{\underline{\underline{Answer:}}}}}$

Given,

• Length of the

simple pendulum = L1 = 1m

• Time = T1 = 2s

• Time = T2 = 1.5s

To Find:-

Change in length.

Formula used:-

T $\propto$ $\sqrt{L}$

Calculations:-

$\frac{T1}{T2}$ = $\sqrt{\frac{L1}{L2}}$

squaring on both sides,

$\frac{T1}{T2}^{2}$= $\frac{L1}{L2}$

L2 = L1 ×$\frac{T1}{T2}^{2}$

L2 =1×$\frac{1.5}{2}^{2}$

=0.5625m

Change in the length of a simple pendulum ,

$\delta{L}$ = L1 - L2

=1-0.5625

=0.4375m