Question

calculate the change that should be a factor in the velocity of a body to maintain the same kinetic energy if the mass of body is increased to 4 times​

Answer 1

Answer:

The classical (non-relativistic) kinetic-energy equation is Eₖ = ½mv².

We want Ek1=12m1v21=Ek2=12m2v22Ek1=12m1v12=Ek2=12m2v22 , where m₂ = 4m₁. Since Ek1=Ek2Ek1=Ek2 , their ratio Ek1Ek2=1.Ek1Ek2=1.

This means that the ratio of the right-hand sides is 1 also:

12m2v2212m1v21=1.12m2v2212m1v12=1.

Substitute 4m₁ for m₂:

12(4m1)v2212m1v21=1.12(4m1)v2212m1v12=1.

Cancel the common factors of ½ and m₁, giving 4v22v21=14v22v12=1 , so v22=v214.v22=v124.

Taking square roots, we get v₂=v12.v₂=v12. The new speed must be ½ the old speed.

Explanation:

hope it helps you Mark me as the BRAINLIEST and send some thank AS much u can PLZZ ❤️