Calculate the change that should be affected in the velocity of. a body to maintain the same kinetic energy , if the mass of the body is increased to four times .
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3
let, velocity be v, m be initial mass
kinetic energy k=mv2/2
here k=constant
because the body has same kinetic energy.
v is inversely proportional to the square root of m
v=1/√m
if m increases to 4 times, the velocity will decrease 1/2 times of initial velocity.
kinetic energy k=mv2/2
here k=constant
because the body has same kinetic energy.
v is inversely proportional to the square root of m
v=1/√m
if m increases to 4 times, the velocity will decrease 1/2 times of initial velocity.
Answered by
2
KE = mv²/2
v² = 2KE /m
v = √(2KE/m)
KE(f) = KE(I)
m2 = 4 m1
v1 = √(2KE/m)
v2 = √( 2KE / 4m)
v2 = √(KE/2m)
v1/v2 = √(2KE/m) / √(KE/2m)
v1/v2 = √2KE x √2m / √m x √(KE)
(v1/v2)² = 2KE x 2m / m x KE
(v1/v2)² = 4
√(v1/v2)² = √4
v1/v2 = 2
v1 = 2 x v2
initial velocity is two times that of final velocity
OR
final velocity will be half on initial velocity
v² = 2KE /m
v = √(2KE/m)
KE(f) = KE(I)
m2 = 4 m1
v1 = √(2KE/m)
v2 = √( 2KE / 4m)
v2 = √(KE/2m)
v1/v2 = √(2KE/m) / √(KE/2m)
v1/v2 = √2KE x √2m / √m x √(KE)
(v1/v2)² = 2KE x 2m / m x KE
(v1/v2)² = 4
√(v1/v2)² = √4
v1/v2 = 2
v1 = 2 x v2
initial velocity is two times that of final velocity
OR
final velocity will be half on initial velocity
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