Calculate the change that should be affected in the velocity of a body to maintain the same kinetic energy, if the mass of the body is increased to four times.
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Answered by
43
Let initial mass of body be m kg and velocity be
V m/s.
Now, kinetic energy (initial) = 1/2 mv^2
Final mass = 4m
Final velocity = V1( let)
Now, final kinetic energy= 1/2×4mv1^2
=2mv1^2
So, acc. To the question
2mv1^2 =1/2mv^2
=>V^2 = 4 V1^2
=> V = 2V1
SO, velocity should be increased 2 times if kinetic energy has to be kept constant.
V m/s.
Now, kinetic energy (initial) = 1/2 mv^2
Final mass = 4m
Final velocity = V1( let)
Now, final kinetic energy= 1/2×4mv1^2
=2mv1^2
So, acc. To the question
2mv1^2 =1/2mv^2
=>V^2 = 4 V1^2
=> V = 2V1
SO, velocity should be increased 2 times if kinetic energy has to be kept constant.
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