Physics, asked by same1853, 16 days ago

calculate the changes in the length of simple pendulum of length 1m when its period of oscillation changes from 2s to 1.55

Answers

Answered by gauravkartiksharma
0

Answer: 16 /7 m.

Explanation:

Answer

Given, T  

1

​  

=2sec

L  

1

​  

=1m

T  

2

​  

=1.5sec

T=2π  

g

L

​  

 

​  

 

Tα  

L

​  

 

L  

2

​  

 

​  

 

T  

1

​  

 

​  

=  

L  

2

​  

 

​  

 

T  

2

​  

 

​  

 

∴  

1

​  

 

2

​  

=  

L  

2

​  

 

​  

 

1.5

​  

 

L  

2

​  

=  

16

9

​  

 

L  

1

​  

−L  

2

​  

=1−  

16

9

​  

 

=  

16

7

​  

 

∴     length decreased  by  

16 /7 m.

Answered by mohdjameelakthar9
0

Answer:

Gauravkartiksharma if you want to answer any questions

answer it properly please don't waste their time

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