Question

Calculate the charge carried by 12.5×10^8 electrons.

Answer 1

Answer:

Charge on one proton = 1.6 * 10^-19 C

So Total charge carried = 12.5 * 10^8 * 1.6 * 10^-19 C

= 2 * 10^ -10 C

Explanation:

please mark as brainlist

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Charge=2\times 10^{-10}\:C}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Number \: of \: electrons(n) = 12.5 \times {10}^{ 8} \: electrons \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Charge \: carried(Q) = ?$

• According to given question :

$\tt \circ \: n = 12.5 \times {10}^{8} \: electron \\ \\ \tt \circ \: e = 1.6 \times {10}^{ - 19} \\ \\ \bold{As \: we \:know \: that} \\ \tt: \implies Q = ne \\ \\ \tt: \implies q = 12.5 \times {10}^{8} \times 1.6 \times {10}^{ - 19} \\ \\ \tt: \implies Q = 12.5 \times 1.6 \times {10}^{8 - 19} \\ \\ \tt: \implies Q = 20 \times {10}^{ - 11} \\ \\ \green{\tt: \implies Q = 2 \times {10}^{ - 10}\:C} \\ \\ \green{\tt \therefore Charge \: carried \: is \: 2 \times {10}^{ - 10} \:C} \\ \\ \bold{ \blue{Some \: related \: formula}} \\ \\ \red {\tt\circ\:Coulomb's\: law:} \\ \orange{ \tt \circ \:F = \frac{k q_{1}q_{2}}{ {r}^{2} } }$