calculate the charge carried by 12.5into1018 electrons
Answers
Answered by
3
Given,
No. of elections= 12.5×10^18=N(let)
the toal charge due to N electrons is
Qe = N*e { e is the fundamental charge =1.6*10-19}
= 1.6*10-19 ×12.5×10^18
=20 *10^-1 C
= 2 C.
hope you understand!!!!
No. of elections= 12.5×10^18=N(let)
the toal charge due to N electrons is
Qe = N*e { e is the fundamental charge =1.6*10-19}
= 1.6*10-19 ×12.5×10^18
=20 *10^-1 C
= 2 C.
hope you understand!!!!
Answered by
3
Answer:
2 C.
Explanation:
hope it is help full to u
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