Math, asked by jokerjokes153, 8 months ago

calculate the charge entering the element from t=0 to t=2s?
the current flowing through an element is:
i= 4A, 4t^2A

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Answers

Answered by mahendrachandra172
6

Answer:

given that

i =4A

time = 2 sec

we know that ,

current = charge / time

therefore charge = current × time = 4A × 2 sec = 8 columbs

so answer is 8 columbs

Answered by amitnrw
11

Given :  current flowing through an element

i = 4    0 < t < 1

  4t²    t > 1

To Find :  the charge entering the element from t=0 to t=2s

Solution:

i = 4    0 < t < 1

  4t²    t > 1

i = dq/dt

dq = i dt

Integrating both sides

=> ∫dq  = ∫ i dt

=> q = ∫ i dt

t=0 to t=2s

q=\int\limits^1_0 {4} \, dt +\int\limits^2_1 {4t^2} \, dt

q=\left 4t \right |^1_0 + \left \frac{4t^3}{3} \right|^2_1

= 4(1) - 4(0)  + 4(2)³/3 - 4(1)³/3

= 4 - 0  + 32/3 - 4/3

= 4 + 28/3

= 40/3  

charge entering the element from t=0 to t=2s is 40/3   C

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