Calculate the charge of a copper particle of mass 300 mg if 0.1%of the electron are removed from it
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Given here: Atomic mass of iron = 56 now, 1 mole of iron contains 56 g of iron. no. of moles in 224 g iron = n= 224/56 = 4 Now, Total number of electrons or protons in 4 moles of iron = n × avagadro number = 4 × 6.032 × 1023 0.01 % of 4 × 6.032 × 1023 = a = (0.01/100) × 4 × 6.032 × 1023 = 2.41×1020 Now, defecient negative charge = a × charge on electron = 2.41×1020 × 1.602 × 10-19 = 38.6 C Positive charge acquired by 224g iron = defecient negative charge = 38.6 CRead more on Sarthaks.com - https://www.sarthaks.com/86899/calculate-the-charges-iron-particle-of-mass-224-mg-if-01-of-the-electrons-are-removed-from?show=90124#a90124
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1299.2 x 10-2 coulomb.
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