Physics, asked by dikshaarya38951, 1 year ago

Calculate the. Charge of a copper particle of mass 300mg if 0.1percent of the electron are removed from it

Answers

Answered by JackelineCasarez
0

0.455 C would be the positive charge, as same as -ve charge removed from it.

Explanation:

Given,

Mass of the particle = 300 mg

As we know,

Copper atom's 1 mole weighs = 63.55 g

No. of moles in 300mg copper = (300 * 10^-3)/63.55 = 4.72 * 10^-3 mol

No. of electrons in 300 mg of copper = 4.72 * 10^-3 * 6.022 * 10^23 * 10^-3

= 28.45 * 10^20 electrons

Now,

0.1% of 28.45 * 10^20 = 0.02845 * 10^20

= 2.845 * 10^18 electrons

Total negative charge removed = 2.845 * 10^18 * 1.602 * 10^-19

= 4.55 * 10^-1

= 0.455 C

Learn more: Negative charge

brainly.in/question/11298308

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