Calculate the charge of an iron particla of mass 224mg if 0.01% of the electron are removed from it
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mass number of Fe = 56 g
moles of Fe = 22.4/56 =0.4
no of electrons in 0.4 moles= 0.4*6.023*10 to power 23 =2.4092*10 to power 23
when .01% electrons are removed then left no of electrons =2.4089*10^23
charge on iron 2.4089*10^23*1.6*10^-19= 38543.34 C
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