Calculate the charge on 6.35g copper. If 2% of it's electron is removed
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ExplanationGiven mass=6.35g
At mass=63.5 Atno.=29(which is total no. Of e-)
No. Total no. Of electrons in 63.5g=6.35×29/63.5
Now in 6.02×10^23 atoms=2.9×6.02×10^23=1.74×10^24
According to the question:
2% of e- is removed i,e no. Of e- left=2×1.74×10^24/100
=1.705×10^24
Now the net charge on cu Q=ne
i,e=1.7×10^24×1.6×10^-19c
=2.72×10^5
I hope u find the answer pretty well.
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