Question

Calculate the charge on each capacitor in the steady state.​

Answer 1

Answer:

In steady state the capacitor becomes open, So current through the circuit, i=27×1039. And Voltage across the capacitor, Vc=i×15 kΩ=15×103×27×1039=315=5V. Charge through the capacitor, q=CVc=9×10−6×5. q=45×10−6C. q=45μC.

Answer 2

for steady state the condition will be fully charged and the current would be zero .