Question

Calculate the charge passing Through a lamp in 2 minutes if the current is 300 milliampere

Answer 1

current=300mA= 0.3A
time= 2 min= 2×60= 120 sec
therefore,
charge= 0.3×120
=>36 coloumb

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Answer 2

Hey!

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Here is solution :-

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1m = 10^-3 ampere

= 300 × 10^-3

= 0.3 Amperes

•Current (I) = Charge(Q) ÷ Time(t)

I = Q ÷ t

•0.3 Ampere = Charge(Q) ÷ time (t)

Q = 120 x 0.3

= 12 × 3

= 36 Coloumb

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Regards :)

Yash Raj ✌