Calculate the charge passing through a lamp in2minutes if the current 300milliampere
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as we know I=q/t
so 300 milliampere =300*1/1000=0.3 ampere
so time =2 min= 120 second s
now q=I*t
=0.3*120=36coulomb of charge
so 300 milliampere =300*1/1000=0.3 ampere
so time =2 min= 120 second s
now q=I*t
=0.3*120=36coulomb of charge
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