Question

Calculate the charge supplied by the battery in the circuit
given below:

C1 = 5HF
C2 =6HF
V = 10 V
​

Answer 1

Answer:

As capacitor 4 and combine (3,2, 5) are in parallel so potential across (3,2,5) V=6V

Equivalent capacitor for (3,2,5) is C

eq

=

3+(2+5)

3(2+5)

=2.1μF

thus, Q

eq

=C

eq

V=2.1×6=12.6μC

As capacitor 3 and (2,5) are in series so charge on 3 and (2,5) is equal to Q

eq

.

Net capacitance for (2,5) is C

(2,5)

=2+5=7μF.

Thus potential across (2,5) is V

2,5

=

C

(2,5)

Q

eq

=

7

12.6

=1.8V

As 2 and 5 are in parallel so potential across each is same. i,e V

2,5

=1.8V

Charge on 5 is Q

5

=C

5

V

2,5

=5(1.8)=9μC

Answer 2

Explanation:

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