calculate the charge which flows through a 600 ohm resistor when a potential difference of 20 volts is applied for 30 seconds across its ends
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Explanation: Given, R= 600ohm
V= 20V
t= 30 sec
q=?
By ohm's law
V=IR
I = V /R
I= 20 /600 = 1/30
As , we know I= q/t
1/30 = q / 30
q = 1 C
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