Question

Calculate the Cl and amount on 3,600 for 3/2 years at 6% per annum if the interest is compounded<br />annually​

Answer 1

solution:

$\sf \: 3618.52$

To find:

Calculate the S.I. unit?

Given:

$\tt {\pink{Given}}\begin{cases} \sf{\green{Principal=Rs.3600}}\\ \sf{\blue{Time= \frac{3}{2} \: Years}}\\ \sf{\orange{Rate=6\%}}\\ \sf{\red{Amount=?}}\end{cases}$

$\implies\boxed{\sf{c.i. = p+(1 + \frac{r}{n}) ^{nt} }}$

$\implies \sf \: {3600 + (1 + \frac{6}{1}) } ^{ \frac{3}{2} }$

$\implies \sf \: 3600 + \sqrt{7^3}$

$\implies \sf \: 3600 + 18.52$

$\implies \sf \: 3618.52(approx)$

Answer 2

Answer:

solution:

\sf \: 3618.523618.52

To find:

Calculate the S.I. unit?

Given:

\begin{gathered}\tt {\pink{Given}}\begin{cases} \sf{\green{Principal=Rs.3600}}\\ \sf{\blue{Time= \frac{3}{2} \: Years}}\\ \sf{\orange{Rate=6\%}}\\ \sf{\red{Amount=?}}\end{cases}\end{gathered}

Given

⎩

⎪

⎪

⎪

⎪

⎨

⎪

⎪

⎪

⎪

⎧

Principal=Rs.3600

Time=

2

3

Years

Rate=6%

Amount=?

\implies\boxed{\sf{c.i. = p+(1 + \frac{r}{n}) ^{nt} }}⟹

c.i.=p+(1+

n

r

)

nt

\implies \sf \: {3600 + (1 + \frac{6}{1}) } ^{ \frac{3}{2} }⟹3600+(1+

1

6

)

2

3

\implies \sf \: 3600 + \sqrt{7^3}⟹3600+

7

3

\implies \sf \: 3600 + 18.52⟹3600+18.52

\implies \sf \: 3618.52(approx)⟹3618.52(approx)