Question

Calculate the co-ordinates of:-

Answer 1

Step-by-step explanation:

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Answer 2

AP = AB/3

AP/AB = 1/3

So,

AP = x ; AB = 3x

Therefore:   PB = AB - AP = 3x - x = 2x

Ratio = AP : PB = x : 2x = 1 : 2

Let coordinates of A be (x,0) and coordinates of B be (0,y)

Section formula

P(4,-2) = P [ (2x + 0) / 3 , (y + 0) / 3]

∴ 4 = 2x/3

x = 6

And,

-2 = y/3

y = -6

i) A(6,0)

ii) B(0, -6)

iii) AB = √[(6 - 0)² (0 + 6)²] = √[2(6^2)] = 6√2 units

iv) Ar.(triangle AOB) = 1/2 x AO x BO = 1/2 x 6 x 6 = 18 units²

(Pls find ao and bo yourself)

Hope I helped