Calculate the coefficient of correlation by Karl Pearson’s Method from the
following data: X 6 2 10 4 8 12
Y 9 11 14 8 7 5
Answers
Answer:
The sales in:
The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores
The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:
The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.
The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.(c) The difference of sales in 2002 and 2006 = Rs.8 crores–Rs.4 crores= Rs.4 crores
The sales in:(i) 2002 was Rs.4 crores and (ii) 2006 was Rs.8 crores(b) The sales in:(i) 2003 was Rs.7 crores and (ii) 2005 was Rs.10 crores.(c) The difference of sales in 2002 and 2006 = Rs.8 crores–Rs.4 crores= Rs.4 crores(d)In the year 2005, there was the greatest difference between the sales and compared to its previous year, which is (Rs. 10crores –Rs. 6crores) = Rs. 4crores.