Question

Calculate the coefficient of cubical expansion of a zinc bar whose volume is increased 0.25m³ from 0.3m³ due to the change in its temperature of 50K?

Answer 1

$\Huge\mathcal{\underline{\blue{Answer\::-}}}$

$\Large{\pink{α = 1.111×10^-3 /K}}$

➣ Explaination -

• Given -

➟V0 = 0.25 m³

➟V = 0.30 m³

➟∆T = 50 K

• Solution -

Change in volume is -

➟∆V = V - V0

➟∆V = 0.30 - 0.25

➟∆V = 0.05 m³

Coefficient of cubical expansion is calculated as -

$\purple{∆V/V0 = 3α∆T}$

➟0.05 / 0.30 = 3 × α × 50

➟α = 1 / (6×3×50)

$\green{➟α = 1.111×10^-3 /K}$

Therefore, coefficient of volume expansion will be 1.111×10^-3 /K.

$\Huge\mathcal{\underline{\red{Hope\:It\: Helps\:U}}}$