Calculate the coefficient of viscosity of hydrogen at STP. Take ρ =8.90x 10×-2 kg/ m3, λ =2x10×-7 m and Kb=1.38x10×-23 J/K .
Answers
Answered by
1
Given:
ρ=8.90x 10⁻² kg/ m3,
λ=2x10⁻⁷ m
Kb=1.38x10⁻²³ J/K .
we know that n=(1/3)ρVλ
V=√(3KT/m)
at STP, T=273k V=22.4x10⁻3m³
m=ρV/Nₐ
⇒(8.90x10⁻²x22.4 x10⁻³)/6.022x10²³
=1.38x10⁻²³ Kg
V=√([3x1.38x10⁻²³ x273)/1.38x10⁻²³ ]
⇒1848m/s
n=(1/3)x[8.90x10⁻²x1848x2x10⁻⁷]
=1.09x10⁻⁵ kg/m.s
ρ=8.90x 10⁻² kg/ m3,
λ=2x10⁻⁷ m
Kb=1.38x10⁻²³ J/K .
we know that n=(1/3)ρVλ
V=√(3KT/m)
at STP, T=273k V=22.4x10⁻3m³
m=ρV/Nₐ
⇒(8.90x10⁻²x22.4 x10⁻³)/6.022x10²³
=1.38x10⁻²³ Kg
V=√([3x1.38x10⁻²³ x273)/1.38x10⁻²³ ]
⇒1848m/s
n=(1/3)x[8.90x10⁻²x1848x2x10⁻⁷]
=1.09x10⁻⁵ kg/m.s
Similar questions