calculate the combined resistences of three resistences 4 omega, 6 omega and 8 omega in series
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Answer:
Explanation:
To get an equivalent resistance of 6 ohms, we have to use both parallel and series connection in the circuit. First, the two resistors are connected in parallel to obtain a combined resistance of 2 ohms and then the combined resistance in connected in series with the third resistor to give a total resistance of 6 ohms.
That is, for the two resistors in parallel the resistance is given as 4
1 + 4 1 = 0.5 1
=2ohms and this is added with the resistance of the third resistor in series as 2+4=6 ohms.
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