Calculate the % composition of each elements in (C2H5OH) ethanol?
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Answered by
99
Percentage composition = (Mass of the element) ×100/ (Molar mass of the compound )
Mass of Carbon = 12
Mass of Hydrogen (H) = 1
Mass of Oxygen (O) = 16
Molar mass of compound = [ (2×12) + 5 + 16 + 1 ]
= ( 46 + 5 + 16 + 1)
= 46 //
% composition of Carbon
------------------------
= ( 24 × 100) / 46
= 52.17
= 52.2 % //
% composition of Hydrogen
-------------------------
= (6 × 100) / 46
= 13.04 % //
% composition of oxygen
----------------------------------
= ( 16 × 100) / 46
= 34.78 % //
Mass of Carbon = 12
Mass of Hydrogen (H) = 1
Mass of Oxygen (O) = 16
Molar mass of compound = [ (2×12) + 5 + 16 + 1 ]
= ( 46 + 5 + 16 + 1)
= 46 //
% composition of Carbon
------------------------
= ( 24 × 100) / 46
= 52.17
= 52.2 % //
% composition of Hydrogen
-------------------------
= (6 × 100) / 46
= 13.04 % //
% composition of oxygen
----------------------------------
= ( 16 × 100) / 46
= 34.78 % //
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