Chemistry, asked by Anushree11, 1 year ago

calculate the % composition of Fe in FeSO4.7H2O
(Fe is 56,S is 4,O is 16,H is 1)

Answers

Answered by Anonymous

Actual ans if S=32
56+32+64+14+16*7=278
% FE=56/278*100==20.14

drbabbarprashant: molecular weight of S is wrong here

Anonymous: thats what i know..as per given values this is ans...buddy

Anonymous: hmm..

Answered by Anonymous

See, here is the solution :

56 + 32 + 64 + 14 + 16 × 7 = 278

Therefore percentage of Fe = 56 / 278 * 100 = 20.14

HOPE IT IS HELPFUL... :)

Anonymous: %fe is asked..find thattt

Anonymous: Yes.. Sorry I edited it but it's not getting edited..

Anonymous: i reported so it cant be i think..sry

Anonymous: okay..

drbabbarprashant: nice

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