Question

calculate the composition of the following
1.ca(h2po4)2[ca=40,H=1,P=31,O=16]
2.caocl2[cl=35.5]
3.[cu(nh3)4]so4[cu=65,n=14,s=32]
4.Al(no3)3[al=27]

Answer 1

Answer:

CaOCl

2

. 2H

2

O →Cl

2

1 mole of CaOCl

2

. 2H

2

O gives 1 mole Cl

2

163 g of sample gives 71g of available Chlorine

Therefore, % available chlorine =

163

71

× 100= 43.5%

Answer 2

Answer:

Explanation:

CaOCl

2

. 2H

2

O →Cl

2

1 mole of CaOCl

2

. 2H

2

O gives 1 mole Cl

2

163 g of sample gives 71g of available Chlorine

Therefore, % available chlorine =

163

71

× 100= 43.5%