Question

calculate the compound interest for second year on rupees 12000 invested for 3 years at 10% per year also find the sum due at the end of 3rd year​

Answer 1

We have to calculate the compound interest for 2nd year on Rs 12,000 invested for 3 years at 10 % per annum. Also find the sum due at the end of 3rd years.

Solution : compound interest for 2nd year = C.I for 2 years - C.I for 1 year

= P(1 + r/100)² - P(1 + r/100)¹

= P(1 + r²/10000 + 2r/100 - 1 - r/100)

= p(r²/10000 + r/100)

= 12,000(100/10000 + 10/100)

= 12,000(1/100 + 1/10)

= 120 × 11

= 1320 Rs.

Sum due at the end of 3rd year = compound interest in 3 years

= P(1 + r/100)³ - P

= 12000(1 + 10/1000)³ - P

= 12000(11/10)³ - 12000

= 12 × 1331 - 12000

= 15972 - 12000

= 3972 Rs.

at the end of 3rd year, they should pay 3972 Rs.

Answer 2

Mark as brainiest a

Step-by-step explanation:

For 1st year

P = 12000

R = 10 %

T = 1 year

S.I. = 12000*10*1/100

= 1200

Amount = 12000+1200

= 13200

For 2nd year

P = 13200

R = 10%

T = 1 year

S.I. = 13200*10*1/100

= 1320

Amount = 13200+1320

= 14520

For 3rd year

P = 14520

R = 10%

T = 1 year

S.I. = 14520*10*1/100

= 1452

Amount at the end of 3 year

= 14520+1452

= 15972