Question

calculate the compound interest of ₹800 for 2 year. When the rate of interest for successive year 6% and 10%

with full solution​

Answer 1

Answer:

P=₹800

T=2 year

R=6%

$∴simple \: Interest, SI = \frac{PTR}{100} \\ = \frac{800 \times2 \times 6 }{100} \\ = 96 \\ ∴amount = s.i + p \\ = 800 + 96 \\ = 896 \\ 2nd \: year \\ principle = amount \: of \: 1st \: year \: = 1280 \\ rate \: of \: interest = 8\% \\ time = 1 \: year$

$∴interest = \frac{896 \times 2 \times 8}{100} \\ = 143.36 \\ ∴amount = 896 + 143.36= 1,039.36$

is this a correct explanation now I hope it helped