Question

Calculate the compound interest on 4000 at 5% p.a. for 1 year , interest being compounded half yearly.

Answer 1

Answer:

compound interest =202.5

Step-by-step explanation:

A=P(1+R/2*100)^T*2

=4000(1+5/200)^1*2

=4000(205/200)^2

=4000*41/40*41/40

=4202.5

C.I=A-P

=4202.5-4000

=202.5

Answer 2

Answer:

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➾ Principle = ₹4000

➾ Rate = 5 %

➾ Time = 1 year

➾ Compounded = half yearly

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➾ Compound Interest = ?

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❒ Formula Used :

$\large{\blue{\bigstar}}{\underline{\boxed{\red{\sf{C.I = P\bigg(1 + \dfrac{R}{100} \bigg)^T - P}}}}}$

➢Here :

➳ C.I = Compound Interest = ?

➳ P = Principle = 4000

➳ R = Rate = 5 %

➳ T = Time = 2T

$\qquad{━━━━━━━━━━━━━━━━━━━━━━━━━━}$

❒ Finding the compound interest :

➙ C.I = P(1 + R/100)^T - P

➙ C.I = 4000(1 + 5/100)^2 - 4000

➙ C.I = 4000(1 + 0.05)^2 - 4000

➙ C.I = 4000(1.05)^2 - 4000

➙ C.I = 4000 × 1.1025 - 4000

➙ C.I = 4410 - 4000

➙ C.I = Rs.410

$\qquad{━━━━━━━━━━━━━━━━━━━━━━━━━━}$

❒ Therefore :

❝ Compound interest on the sum of Rs.4000 is ₹ 410 . ❞

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