Question

Calculate the compound interest on 6000 at 10% per annum for two years.,​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{C.I=1,260\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given :}} \\ \tt: {\implies Principal(p) = 6,000 \: rupees} \\ \\ \tt: \implies Time(t)= 2\: years \\ \\ \tt: \implies Rate\% = 10\% \\ \\ \red{ \underline \bold{To \: Find:}} \\ \tt:\implies Compound\:Interest=?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A = p(1 + \frac{r}{100} )^{t} \\ \\ \tt: \implies A = 6000(1 + \frac{10}{100} )^{2} \\ \\ \tt: \implies A =6000( 1 + 0.1)^{2} \\ \\ \tt: \implies A = 6000(1.1)^{2} \\ \\ \tt: \implies A = 6000\times 1.21 \\ \\ \green{\tt: \implies A= 7,260\: rupees}$

$\bold{As \: we \: know \: that} \\ \tt: \implies C.I = A-p \\ \\ \tt:\implies C.I=7260-6000 \\ \\ \green{\tt: \implies C.I= 1,260\: rupees}$

Answer 2

$\huge{\underline{\underline{\mathtt{\blue{ANSWER}}}}}$

$\mathtt{⟹ \:Rs\: 1260}$

$\huge{\underline{\mathtt{\blue{SOLUTION}}}}$

$\mathtt\orange{GIVEN}$

$\mathtt{.⟹ \: Principal\: =\: 6000 }$

$\mathtt{⟹ \: Rate \: =\: 10\: }$

$\mathtt{⟹ \: Time\: = \: 2 \: years}$

$\mathtt\orange{To \: Find}$

$\mathtt{⟹ Compound\: interest}$

$\mathtt\orange{⟹Formula}$

$\mathtt{compound \: interest = p( {1 + \frac{r}{100} }^{n \: years} - p}$

$\mathtt{⟹ \: 6000( {1 + \frac{10}{100} }^{2}) - 6000}$

$\mathtt{⟹ (\: 60 \times 11 \times 11) - 6000}$

$\mathtt{⟹ 60 \times121}$ - $\mathtt{6000}$

$\mathtt\blue{⟹ 7260 \: - \: 6000}$

$\huge{\boxed{\mathtt{\blue{1260}}}}$