Question

Calculate the compound interest on 6000 at 10% per annum for two years​

Answer 1

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Heya friend,

Given that

P = ₹6,000

R = 10 % p.a.

T = 2 years

Solution

C.I. = P{(1+R/100)^ n - 1}

= 6,000{(1+10/100)^2 - 1}

= 6,000{(100+10/100)^2 - 1}

= 6,000{(110/100)^2 - 1}

= 6,000{(11/10)^2 - 1}

= 6,000{121/100 - 1}

= 6,000{121-100/100}

= 6,000 × 21/100

= ₹1,260

Answer 2

Answer:



Given that

P = ₹6,000

R = 10 % p.a.

T = 2 years

Solution

C.I. = P{(1+R/100)^ n - 1}

= 6,000{(1+10/100)^2 - 1}

= 6,000{(100+10/100)^2 - 1}

= 6,000{(110/100)^2 - 1}

= 6,000{(11/10)^2 - 1}

= 6,000{121/100 - 1}

= 6,000{121-100/100}

= 6,000 × 21/100

= ₹1,260

Hope it helps

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