Calculate the compound interest on 6000 per 10% per minimum for 2 years
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Given:-
- Principal (P) = Rs.6000
- Rate (R) = 10 % p.a.
- Time (T) = 2 years
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To find:-
- Compound interest.
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Solution:-
According to the question,
→ C.I. = P{(1 + R/100)ⁿ - 1}
→ 6,000{(1 + 10/100)² - 1}
→ 6,000{(100 + 10/100)² - 1}
→ 6,000{(110/100)² - 1}
→ 6,000{(11/10)² - 1}
→ 6,000{121/100 - 1}
→ 6,000{121 - 100/100}
→ 6,000 × 21/100
→ Rs.1,260
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Hence,
- the compound interest is Rs.1,260.
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