Question

calculate the compound interest on ₹7500 at 7% per annum for 2 years
​

Answer 1

Given:

• Principal (p) = ₹ 7500
• Rate of Interest (R) = 7 % p.a
• Time (n) = 2 years

To find:

• The Compound Interest (C.I)

The formula for finding the Compound Interest (C.I) is

$\boxed{\boxed{\sf C.I = \bf P [ (1+\frac{R}{100})^{n}-1] }}$

Now,

Putting the give values

$\tt C.I = 7500 [ (1+\frac{7}{100})^{2}-1]$

$\tt C.I = 7500 [ (\frac{100+7}{100})^{2}-1]$

$\tt C.I = 7500 [ (\frac{107}{100})^{2}-1]$

$\tt C.I = 7500 [ (\frac{11449}{10000})-1]$

$\tt C.I = 7500 [ (\frac{11449-10000}{10000})]$

$\tt C.I = 7500 * \frac{1449}{10000}$

$\tt C.I = 75 * \frac{1449}{100}$

$\tt C.I = \frac{108675}{100}$

$\bf C.I = 1086.75$

Hence,

The Compound Interest (C.I) is ₹ 1086.75

More Information,

• Simple Interest (S.I) = (P*R*T)/100

Here, P = Principal, R = Rate of Interest, and T = Time

• Amount (A) = P[1 + (R/100)]ⁿ

Here, P = Principal, R = Rate of Interest, and (n) = Time

Answer 2

Answer:

Math

5 points

khushidhatterwal20 • Helping Hand

5.0

6

Given:

•

Principal (p) = ₹ 7500

•

Rate of Interest (R) = 7 % p.a

•

Time (n) = 2 years

To find:

•

The Compound Interest (C.I)

The formula for finding the Compound Interest (C.I) is

\boxed{\boxed{\sf C.I = \bf P [ (1+\frac{R}{100})^{n}-1] }}

Now,

Putting the give values

\tt C.I = 7500 [ (1+\frac{7}{100})^{2}-1]

\tt C.I = 7500 [ (\frac{100+7}{100})^{2}-1]

\tt C.I = 7500 [ (\frac{107}{100})^{2}-1]

\tt C.I = 7500 [ (\frac{11449}{10000})-1]

\tt C.I = 7500 [ (\frac{11449-10000}{10000})]

ANSWER

\tt C.I = 7500 * \frac{1449}{10000}

\tt C.I = 75 * \frac{1449}{100}