calculate the compound interest on rs 9000 for 2 years at 10 p.a by simply interest method for two consecutive year ( finding separately ) ?
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Step-by-step explanation:
1st year
P= ₹9000
T = 1yr
R = 10% p. a.
so, SI = PRT / 100
= ₹ 9000 * 10 * 1 / 100
= ₹900
A = ₹ (9000 + 900)
=₹ 9900
2nd year
P= ₹ 9900
so, SI = PRT / 100
= ₹ 9900*10*1/100
=₹ 990
A= ₹ (9900+990)
= ₹ 10890
so, CI = ₹( 10890 - 9000)
=₹ 1890
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