calculate the compound interest on rs 9000 for 2 years at 10 p.a by simply interest method for two consecutive year ( finding separately ) ?
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Answer:
interest = 18000 amount =
Step-by-step explanation:
p= principal
r = rate
t = time
S.I = P x R x T / 100
9000 x 2 x 10 / 100
1800000 / 100
interest = rs 18000
amount = P + S.I
= 9000 + 18000
= 27000
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