Question

Calculate the compound interest on rupees 12500 for 2 years at 6 % per annum ?

Answer 1

Answer:

p=12500

r=6%

t=2y

C. I=p(1+r) ntimes

=12500(1+6/100) 2

=12500(106/100) 2

=12500×106/100×106/100

=14045

Answer 2

Given :-

• Principal = Rs. 12,500
• Time = 2 years
• Rate = 6%

To find :-

• Compound Interest = ?

Solution :-

$\sf{Amount~=~P[1+ \dfrac{r}{100}]^n}$

$\sf{~=~12500 \bigg[1+ \dfrac{6}{100} \bigg]^2}$

$\sf{~=~12500 \bigg[1+ \dfrac{3}{50} \bigg]^2}$

$\sf{~=~12500 \bigg[ \dfrac{53}{50} \bigg]^2}$

$\sf{~=~12500 \times \dfrac{53}{50} \times \dfrac{53}{50} }$

$\sf{Rs. \: 14,045}$

• $\sf{Compound~Interest~=~Amount - Principal}$

C.I. = Rs. 14,045 - Rs. 12,500

• C.I. = Rs. 1,545

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Some related formulae :-

• $\sf{C.I.~=~A - P}$
• $\sf{A = C.I. + P}$